1 条题解
- 
  0
C :
#include <stdio.h> int main() {double res; res = (9.5*4.5-2.5*3)/(45.5-3.5); printf("%.2f",res); return 0; }C++ :
#include<iostream> using namespace std; int main() { cout.precision(2); cout << (9.5*4.5 - 2.5 * 3) / (45.5 - 3.5) << endl; getchar(); return 0; }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { double a=(9.5*4.5-2.5*3)/(45.5-3.5); a=Math.round(a*100); System.out.print(a/100); } }Python :
a = ((9.5*4.5)-(2.5*3))/(45.5-3.5) print ('%.2f' % a) 
- 1
 
信息
- ID
 - 2227
 - 时间
 - 1000ms
 - 内存
 - 128MiB
 - 难度
 - (无)
 - 标签
 - 递交数
 - 0
 - 已通过
 - 0
 - 上传者