1 solutions

  • 0
    @ 2024-12-4 19:37:03

    C++ :

    #include <iostream>
    using namespace std;
    #define N 6
    int a[N];
    void f(int k)
    {
    	int i;
    	if(k==N)
    	{
    		int sum=0;
    		for(i=0;i<N;i++)
    			sum+=a[i];
    		bool b1,b2,b3,b4;
    		b1=a[1]+a[2]==2||a[0]==0;
    		b2=a[2]+a[3]==0||a[4]==0;
    		b3=a[5]==0||a[4]==1;
    		b4=a[0]==1;
    		if(sum==4&&b1&&b2&&b3&&b4)
    		{
    			for(i=0;i<N;i++)
    				if(a[i]==0)
    					cout<<char('A'+i);
    			cout<<endl;
    		}
    		return;
    	}
    	for(i=0;i<2;i++)
    	{
    		a[k]=i;
    		f(k+1);
    	}
    }
    int main()
    {	
    	f(0);
    	return 0;
    }
    
    
    • 1

    Information

    ID
    2247
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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