1 solutions
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0
C++ :
#include <iostream> using namespace std; #define N 6 int a[N]; void f(int k) { int i; if(k==N) { int sum=0; for(i=0;i<N;i++) sum+=a[i]; bool b1,b2,b3,b4; b1=a[1]+a[2]==2||a[0]==0; b2=a[2]+a[3]==0||a[4]==0; b3=a[5]==0||a[4]==1; b4=a[0]==1; if(sum==4&&b1&&b2&&b3&&b4) { for(i=0;i<N;i++) if(a[i]==0) cout<<char('A'+i); cout<<endl; } return; } for(i=0;i<2;i++) { a[k]=i; f(k+1); } } int main() { f(0); return 0; }
- 1
Information
- ID
- 2247
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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