1 solutions
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0
C++ :
#include <bits/stdc++.h> #define N 1010 using namespace std; int T, m, n, K, x, y, d; int dir[4][2] = {0, 1, 1, 0, 0, -1, -1, 0}; char mm[N][N]; bool vis[N][N]; bool ok(int u, int v) // 判断位置(u,v)是否合法 { if (u < 1 || u > m || v < 1 || v > n) return 0; if (mm[u][v] != '.') return 0; return 1; } int main() { cin >> T; while (T--) { memset(vis, 0, sizeof(vis)); scanf("%d%d%d", &m, &n, &K); scanf("%d%d%d", &x, &y, &d); for (int i = 1; i <= m; i++) scanf("%s", mm[i] + 1); vis[x][y] = 1; while (K--) { int nx, ny; nx = x + dir[d][0]; ny = y + dir[d][1]; if (!ok(nx, ny)) { d = (d + 1) % 4; continue; } x = nx, y = ny; vis[x][y] = 1; } int ans = 0; for (int i = 1; i <= m; i++) for (int j = 1; j <= n; j++) if (vis[i][j]) ans++; printf("%d\n", ans); } }
- 1
Information
- ID
- 5610
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 0
- Uploaded By