1 solutions
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0
C++ :
#include<iostream> #include<math.h> using namespace std; typedef long long ll; ll n,e,d,m,k,q,p; int main(){ scanf("%lld",&k); for(int i=1;i<=k;i++){ scanf("%lld%lld%lld",&n,&e,&d); m=n-e*d+2; ll x=sqrt(m*m-4*n); if(x*x!=m*m-4*n){ printf("NO\n"); } else{ printf("%lld %lld\n",(m-x)/2,(m+x)/2); } } }
- 1
Information
- ID
- 9131
- Time
- 1000ms
- Memory
- 512MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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