1 solutions

  • 0
    @ 2024-12-5 18:22:02

    C++ :

     #include<iostream>
                   #include<cmath>
                   using namespace std;
                   int main(){
                         int x,y,time;
                         cin>>x>>y>>time;
                         int aa[x*y],sum=0,time_z=0,x_z[x*y]={0},y_z[x*y]={0},b=0,s=0,t=0,bb=0;
                         for(int i=0;i<x*y;i++){
                            cin>>aa[i];
                            if(aa[i]!=0)b++;
                        }
                        while(s<b){
                              for(int i=0;i<x*y;i++){
                                 for(int j=0;j<x*y;j++)
                                     if(aa[i]>=aa[j]) t++;
                                                 if(t==x*y-s){
       	                                               x_z[s]=i/y;
                                                       y_z[s]=i%y;
                                                       t=0;
                                                       break;
                                                  }
                                                  t=0;
                                        }
                                        s++;
                          }
                          for(int i=0;i<x*y;i++){
    	                       for(int j=i+1;j<x*y;j++){
                                          if(aa[i]<aa[j]){
    	                                      int temp=aa[i];
    	                                      aa[i]=aa[j];
    	                                      aa[j]=temp;
                                          }
                                 }
                                 bb++;
                                 if(bb>=b)break;
                           }
                           int xxo=-1,yyo=y_z[0];
                           for(int i=0;i<b;i++){
    	                             sum+=aa[i];
    	                             time_z+=abs(x_z[i]-xxo)+abs(y_z[i]-yyo);
    	                             time_z+=1;
    	                             xxo=x_z[i];
    	                             yyo=y_z[i];
                                     if(time_z+xxo+1>time){
        	                              sum-=aa[i];
        	                              break;
    	                             }
                            }
                            cout<<sum<<endl;
                            return 0;}           
    
    • 1

    Information

    ID
    9178
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By