1 solutions
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0
C++ :
#include<iostream> #include<cmath> using namespace std; int main(){ int x,y,time; cin>>x>>y>>time; int aa[x*y],sum=0,time_z=0,x_z[x*y]={0},y_z[x*y]={0},b=0,s=0,t=0,bb=0; for(int i=0;i<x*y;i++){ cin>>aa[i]; if(aa[i]!=0)b++; } while(s<b){ for(int i=0;i<x*y;i++){ for(int j=0;j<x*y;j++) if(aa[i]>=aa[j]) t++; if(t==x*y-s){ x_z[s]=i/y; y_z[s]=i%y; t=0; break; } t=0; } s++; } for(int i=0;i<x*y;i++){ for(int j=i+1;j<x*y;j++){ if(aa[i]<aa[j]){ int temp=aa[i]; aa[i]=aa[j]; aa[j]=temp; } } bb++; if(bb>=b)break; } int xxo=-1,yyo=y_z[0]; for(int i=0;i<b;i++){ sum+=aa[i]; time_z+=abs(x_z[i]-xxo)+abs(y_z[i]-yyo); time_z+=1; xxo=x_z[i]; yyo=y_z[i]; if(time_z+xxo+1>time){ sum-=aa[i]; break; } } cout<<sum<<endl; return 0;}
- 1
Information
- ID
- 9178
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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