1 solutions
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0
C++ :
#include <cstdio> #include <cstring> #include <algorithm> #include <set> #include<bits/stdc++.h> using namespace std; typedef long long ll; #define space putchar(' ') #define enter putchar('\n') typedef pair<int,int> PII; const int mod=1e4+7; const int N=2e6+10; const int inf=0x7f7f7f7f; ll gcd(ll a,ll b) { return b==0?a:gcd(b,a%b); } ll lcm(ll a,ll b) { return a*(b/gcd(a,b)); } template <class T> void read(T &x) { char c; bool op = 0; while(c = getchar(), c < '0' || c > '9') if(c == '-') op = 1; x = c - '0'; while(c = getchar(), c >= '0' && c <= '9') x = x * 10 + c - '0'; if(op) x = -x; } template <class T> void write(T x) { if(x < 0) x = -x, putchar('-'); if(x >= 10) write(x / 10); putchar('0' + x % 10); } int fa[N]; int n,k; PII a[N],sum[N]; int dp[50][50]; int main() { read(n),read(k); dp[0][1]=1; for(int i=1;i<=k;i++) { for(int j=1;j<=n;j++) { if(j==1) dp[i][j]=dp[i-1][n]+dp[i-1][j+1]; else if(j==n) dp[i][j]=dp[i-1][n-1]+dp[i-1][1]; else dp[i][j]=dp[i-1][j-1]+dp[i-1][j+1]; } } write(dp[k][1]); return 0; }
- 1
Information
- ID
- 9185
- Time
- 1000ms
- Memory
- 50MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By