1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; typedef unsigned long long ULL; const int N=1000100,base=131; char str[N]; ULL h[N],p[N]; //求l~r之间的hash值 ULL get(int l,int r){ return h[r] - h[l-1] * p[r-l+1]; } int main() { scanf("%s",str+1); int n = strlen(str+1); p[0] = 1; for(int i = 1;i <= n;i++){ //将小写字母映射为1~26 h[i] = h[i-1] * 131 + (str[i] - 'a' + 1); p[i] = p[i-1] * base; } int l1,r1,l2,r2; cin>>n; for(int i = 1;i <= n;i++){ scanf("%d%d%d%d",&l1,&r1,&l2,&r2); if(get(l1,r1)==get(l2,r2)){ printf("%s\n","Yes"); }else{ printf("%s\n","No"); } } }
- 1
Information
- ID
- 9957
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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