1 solutions

  • 0
    @ 2025-3-3 16:21:28

    C++ :

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    
    using namespace std;
    
    int fa[200004];
    int n,m,l,r,tot,ans,k;
    
    inline int read(){
        int x=0,f=1;
        char ch=getchar();
        while(ch<'0'||ch>'9'){
            if(ch=='-')f=-1;
            ch=getchar();
        }
        while(ch>='0'&&ch<='9'){
            x=x*10+ch-'0';
            ch=getchar();
        }
        return x*f;
    }//快读 
    
    struct node{
        int fir;//第一个点 
        int sec;//第二个点 
        int data;//边权 
    }edge[400005];
    
    inline int find(int x){
        if(x==fa[x])return x;
        else return fa[x]=find(fa[x]);
    }
    
    inline bool cmp(node a,node b){
        return a.data<b.data;//结构体排序 
    }
    
    inline void kruskal(){
        for(register int i=1;i<=m;i++){
            l=find(edge[i].fir);
            r=find(edge[i].sec);
            if(l==r)continue ;//如果联通就跳过 
            fa[l]=r;//否则就合并 
            k=edge[i].data;//每次更新边权,最后一条边为最大 
        //  maxn=max(maxn,edge[i].data);每次加边取max也可以 
            tot++;
            if(tot==n-1)break;
        }
    }
    
    int main(){
        n=read();
        m=read();
        for(register int i=1;i<=n;i++)
        fa[i]=i;//初始化并查集 
        for(register int i=1;i<=m;i++){
            edge[i].fir=read();
            edge[i].sec=read();
            edge[i].data=read();
        }
    
        sort(edge+1,edge+m+1,cmp);//将边权排序,每次加小的 
        kruskal();
        cout<<k;//我喜欢cout...
    
        return 0;
    }
    
    • 1

    Information

    ID
    9973
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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