1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int n,m,k; int f[20001]; int t[20001]; int cnt,a[20001]; bool u[20001]; int ans; int find(int x) { if(f[x]==x) return f[x]; f[x]=find(f[x]); return f[x]; } void merge(int x,int y) { f[find(x)]=f[find(y)]; } int main() { scanf("%d%d%d",&n,&m,&k); for(int i=1;i<=n;i++) f[i]=i; for(int i=1;i<=k;i++) { int x,y; scanf("%d%d",&x,&y); if(find(x)!=find(y)) merge(x,y); } for(int i=1;i<=n;i++) f[i]=find(f[i]); for(int i=1;i<=n;i++) t[f[i]]++; for(int i=1;i<=n;i++) { if(t[i]) { a[++cnt]=t[i]; } } u[0]=1; for(int i=1;i<=cnt;i++) { for(int j=n-a[i];j>=0;j--) { if(u[j]) u[j+a[i]]=1; } } for(int i=1;i<=n;i++) { if(u[i]&&abs(ans-m)>abs(i-m)) ans=i; } printf("%d",ans); return 0; }
- 1
Information
- ID
- 9975
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By