1 solutions

  • 0
    @ 2025-3-3 16:24:07

    C :

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    int G[510][510];
    int n, f;
    int path[2000];
    int degree[510];
    int index;
    
    void dfs(int u){
    for(int v = 1;v <= n; v++){
        if(G[u][v]){
            G[u][v]--;
            G[v][u]--;
            dfs(v);
        }
    }
    path[index++] = u;
    }
    
    int main()
    {
        while(scanf("%d",&f) != EOF){
            memset(G,0,sizeof(G));
            memset(path,0,sizeof(path));
            memset(degree,0,sizeof(degree));
            n = 0;
            for(int i = 0;i < f; i++){
                int a, b;
                scanf("%d%d",&a,&b);
                G[a][b]++;
                G[b][a]++;
                degree[a]++;
                degree[b]++;
                int temp = a < b ? b : a;
                n = n < temp ? temp : n;
            }
            int st = 1;
            for(int i = 1;i <= n; i++){
                if((degree[i] & 1) == 1){
                    st = i;
                    break;
                }
            }
            index = 0;
            dfs(st);
            for(int i = index-1;i>=0;i--){
                printf("%d\n",path[i]);
            }
        }
        return 0;
    }
    

    C++ :

    #include<iostream> 
    #define MAX 1024
    using namespace std;
    int g[MAX][MAX]={0};
    int d[MAX]={0};
    int r[MAX]={0};
    int n=0,e,a,b,m=0;
    void in();
    void find(int i);
    void out();
    int main()
    {
    	in();
    	for(int i=1;i<n+1;i++)
    	{
    		if(d[i]%2==1)
    		{
    			find(i);
    			out();
    			return 0;
    		}
    	}
    	find(1);
    	out();
    	return 0;
    }
    void in() {
    	cin>>e;
    	for(int i=1;i<e+1;i++)
    	{
    		cin>>a>>b;
    		m=max(a,b);
    		n=max(n,m);
    		g[a][b]++;
    		g[b][a]++;
    		d[a]++;
    		d[b]++;
    	}
    }
    void find(int i) {
    	for(int j=1;j<n+1;j++)
    	{
    		if(g[i][j]>0)
    		{
    			g[i][j]--;
    			g[j][i]--;
    			find(j);
    		}
    	}
    	r[++r[0]]=i;
    }
    void out() {
    	for(int i=r[0];i>0;i--)
    	{
    		cout<<r[i]<<endl;
    	}
    }
    
    • 1

    Information

    ID
    9996
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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